Finding Duplicates with SQL

problem:make some selection in database OTHER THEN top (10) post
solution:  provide, table named news with element: newsID, newsDate
SELECT * FROM News WHERE (newsID NOT IN (SELECT TOP (10) newsID FROM News AS News_1 ORDER BY newsDate DESC)) ORDER BY newsDate DESC 
 
it will return all post except top 10 post 

problem:
display age with sql command

solution:
sql command:
SELECT     DATEDIFF(mm, dateOfBirth, GETDATE()) / 12 AS age
FROM         someTable
it wil display age ^^V

problem:

displaying list of bday boy/girl in next (30/ according to your own choice ) days from the current date.

solution:
im using the sql to select the date of birth, for displaying, you can use whatever you want, like gridview, datalist etc.

hereby the sql command:

SELECT     DateOfBirth
FROM         someTablename
WHERE     (DateOfBirth < GETDATE()) AND (DATEDIFF(d, GETDATE(), DATEADD(yy, DATEDIFF(yy, DateOfBirth, GETDATE()), More >

SELECT previous row or "LIMIT-command" in MSSQL

SELECT TOP (1) FROM table_name WHERE (ID< @ID)
ORDER BY ID DESC

SELECT next row or "LIMIT-command" in MSSQL

SELECT TOP (1) FROM table_name WHERE (ID> @ID)
ORDER BY ID

Thank also for the descussion